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Harikishore B - 2nd Year CSE A 180501052 #148

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Harikishore B - 2nd Year CSE A 180501052 #148

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1a8fc82
180501052
Harikishore4461 Oct 8, 2019
2195eb6
180501052
Harikishore4461 Oct 8, 2019
21a8043
180501052
Harikishore4461 Oct 13, 2019
b062d72
Merge pull request #1 from ASS-G/master
Harikishore4461 Oct 13, 2019
6951dbc
180501052
Harikishore4461 Oct 13, 2019
223da1b
180501052
Harikishore4461 Oct 13, 2019
fd8c880
180501052
Harikishore4461 Oct 13, 2019
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11 changes: 11 additions & 0 deletions Assignment 2/180501052/attendanceStudents.py
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Original file line number Diff line number Diff line change
@@ -0,0 +1,11 @@
l=[]
x=int(input("Enter no of student"))
print("Enter your string")
for i in range(0,x):
a=str(input())
l.append(a)
print("The students present were:")
for j in l:
z="P" in j
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@jyuvaraj03 jyuvaraj03 Oct 13, 2019

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There's a flaw in your logic here. Checking if 'P' is in the string will lead to marking people with 'P' in their names present, even when they are absent. Think of the following test case:
Priya-A

Your code will mark Priya as present even when absent. Correct the code, commit the changes and comment acknowledging the same.

if(z):
print(j[0:-2],end=" ")
11 changes: 11 additions & 0 deletions Assignment 2/180501052/occurances.py
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Original file line number Diff line number Diff line change
@@ -0,0 +1,11 @@
x =str(input("Enter the String:"))
a = {}

for i in x:
if i in a:
a[i] += 1
else:
a[i] = 1
print("Occurences")
for j,y in a.items():
print(j,y)
7 changes: 7 additions & 0 deletions Assignment 2/180501052/robberThief.py
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x =int(input("Enter the amount robbed by the thief:"))
if x < 5000:
print("Loss")
if x > 19999:
print("Good")
if x>4999 and x<20000:
print("Moderate")